(t-5/3)^2=49

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Solution for (t-5/3)^2=49 equation: 


t in (-oo:+oo)

(t-(5/3))^2 = 49 // - 49

(t-(5/3))^2-49 = 0

(t-5/3)^2-49 = 0

(t-5/3)^2-49 = 0

t^2-10/3*t-416/9 = 0

t^2-10/3*t-416/9 = 0

t^2-10/3*t-416/9 = 0

DELTA = (-10/3)^2-(-416/9*1*4)

DELTA = 196

DELTA > 0

t = (196^(1/2)+10/3)/(1*2) or t = (10/3-196^(1/2))/(1*2)

t = 26/3 or t = -16/3

(t+16/3)*(t-26/3) = 0

(t+16/3)*(t-26/3) = 0

( t+16/3 )

t+16/3 = 0 // - 16/3

t = -16/3

( t-26/3 )

t-26/3 = 0 // + 26/3

t = 26/3

t in { -16/3, 26/3 }

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